How To Get Tomato Ball In Red Ball 4?

The bag contains 2 White, 3 Black and 4 Red balls. So, total 9 balls are there in the bag; among them 3 are Black and 6 are non-Black balls. Three balls can randomly be drawn in (9C3) = 84 ways. 1 Black and 2 non-Black balls can be drawn in (3C1)* (6C2) = 45 ways. 1 non-Black and 2 Black balls can be drawn in (6C1)* (3C2) = 18 ways.

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Considering this,How many balls are in the first bag?

The first bag contains 8 balls (3 red & 5 black) while the second bag contains 10 balls (6 red &4 black). Probability of drawing a black ball from first bag is 5/8 while that of drawing a black ball from second is 4/10. Hence, the required probability is 5/8 x 4/10 = 1/4.

Herein,How many yellow balls can you put in a box?

Out of the 5 available spaces, 3 spaces can be selected in 5C3 ways to insert the yellow balls. In the remaining 2 places, the green balls can be placed in 1 way. Hence total number of arrangements such that no two balls of the same colour are next to each other = 5C3 = 10. A box contains 4 red balls, 3 blue balls and 5 yellow balls.

Subsequently, question is,How many red and blue balls are in a box?

There are 12 balls in the box of which 4 are red, 3 are blue and 5 are yellow. Now, there will be 3 situations where out of 5 balls drawn there will be exactly 3 red balls are (i) 3 red balls and 2 blue balls (ii) 3 red balls and 2 yellow balls and (iii) 3 red balls and 1 ball each of blue and yellow.

How many red balls are in a bag?

There are 3 red balls and 3 blue balls in a bag. If two balls are drawn at random from the bag, what is the probability of getting one red ball and one blue ball? The probability of this does not depend on order, as expressed, so the first ball is certain to be one of the colors (Panyball = 1).

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